MySQL查询今天、昨天、上周、近30天、去年等的数据的方法

mysql教程 9月前 0 27

一、MySQL查询今天、昨天、上周、近30天、去年等的数据的方法：

#删除建立时间超过3天的订单记录

delete 订单表 where datediff( dd, order_addtime, getdate() ) > 3 用函数datediff() datediff( dd, 时间1, 时间2 )，意思是：计算时间1到时间2之间的天数所以，datediff( dd, order_addtime, getdate() ) > 3，就是超过3天的

#今天

select * from 表名 where to_days(时间字段名) = to_days(now());

#昨天
SELECT * FROM 表名 WHERE TO_DAYS(NOW( ) ) – TO_DAYS( 时间字段名) <= 1

#7天
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <=date(时间字段名)

#近30天
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <=date(时间字段名)

#本月
SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, ‘%Y%m’ ) =DATE_FORMAT( CURDATE( ) , ‘%Y%m’ )

#上一月
SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m’ ) , date_format( 时间字段名, ‘%Y%m’ ) ) =1

#查询本季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());

#查询上季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));

#查询本年数据
select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());

#查询上年数据
select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));

#查询当前这周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,’%Y-%m-%d’)) = YEARWEEK(now());

#查询上周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,’%Y-%m-%d’)) =YEARWEEK(now())-1;

#查询当前月份的数据
select name,submittime from enterprise where date_format(submittime,’%Y-%m’)=date_format(now(),’%Y-%m’)

#查询距离当前现在6个月的数据
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
查询上个月的数据
select name,submittime from enterprise where date_format(submittime,’%Y-%m’)=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),’%Y-%m’)
select * from ` user ` where DATE_FORMAT(pudate, ‘ %Y%m ‘ ) = DATE_FORMAT(CURDATE(), ‘ %Y%m ‘ ) ;
select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,’%y-%m-%d’)) = WEEKOFYEAR(now())
select *
from user
where MONTH (FROM_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = MONTH (now())
select *
from [ user ]
where YEAR (FROM_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = YEAR (now())
and MONTH (FROM_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = MONTH (now())
select *
from [ user ]
where pudate between 上月最后一天
and 下月第一天
where date(regdate) = curdate();
select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())
SELECT date( c_instime ) ,curdate( )
FROM `t_score`
WHERE 1
LIMIT 0 , 30